5x(x+5)=40x+5(x^2+11)

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Solution for 5x(x+5)=40x+5(x^2+11) equation: 



5x(x+5)=40x+5(x^2+11)

We move all terms to the left:

5x(x+5)-(40x+5(x^2+11))=0

We multiply parentheses

5x^2+25x-(40x+5(x^2+11))=0



We calculate terms in parentheses: -(40x+5(x^2+11)), so:

40x+5(x^2+11)

We multiply parentheses

5x^2+40x+55

Back to the equation:

-(5x^2+40x+55)



We get rid of parentheses

5x^2-5x^2+25x-40x-55=0

We add all the numbers together, and all the variables

-15x-55=0

We move all terms containing x to the left, all other terms to the right

-15x=55

x=55/-15

x=-3+2/3

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